Integrand size = 25, antiderivative size = 85 \[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\frac {x}{15 d^2 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {1}{5 e^2 (d+e x) \left (d^2-e^2 x^2\right )^{3/2}}+\frac {2 x}{15 d^4 e \sqrt {d^2-e^2 x^2}} \]
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Time = 0.02 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {807, 198, 197} \[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\frac {x}{15 d^2 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {1}{5 e^2 (d+e x) \left (d^2-e^2 x^2\right )^{3/2}}+\frac {2 x}{15 d^4 e \sqrt {d^2-e^2 x^2}} \]
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Rule 197
Rule 198
Rule 807
Rubi steps \begin{align*} \text {integral}& = \frac {1}{5 e^2 (d+e x) \left (d^2-e^2 x^2\right )^{3/2}}+\frac {\int \frac {1}{\left (d^2-e^2 x^2\right )^{5/2}} \, dx}{5 e} \\ & = \frac {x}{15 d^2 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {1}{5 e^2 (d+e x) \left (d^2-e^2 x^2\right )^{3/2}}+\frac {2 \int \frac {1}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx}{15 d^2 e} \\ & = \frac {x}{15 d^2 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {1}{5 e^2 (d+e x) \left (d^2-e^2 x^2\right )^{3/2}}+\frac {2 x}{15 d^4 e \sqrt {d^2-e^2 x^2}} \\ \end{align*}
Time = 0.28 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.96 \[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (3 d^4+3 d^3 e x+3 d^2 e^2 x^2-2 d e^3 x^3-2 e^4 x^4\right )}{15 d^4 e^2 (d-e x)^2 (d+e x)^3} \]
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Time = 0.37 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.82
method | result | size |
gosper | \(\frac {\left (-e x +d \right ) \left (-2 e^{4} x^{4}-2 d \,e^{3} x^{3}+3 d^{2} e^{2} x^{2}+3 d^{3} e x +3 d^{4}\right )}{15 d^{4} e^{2} \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}\) | \(70\) |
trager | \(\frac {\left (-2 e^{4} x^{4}-2 d \,e^{3} x^{3}+3 d^{2} e^{2} x^{2}+3 d^{3} e x +3 d^{4}\right ) \sqrt {-e^{2} x^{2}+d^{2}}}{15 d^{4} \left (e x +d \right )^{3} \left (-e x +d \right )^{2} e^{2}}\) | \(79\) |
default | \(\frac {\frac {x}{3 d^{2} \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {2 x}{3 d^{4} \sqrt {-e^{2} x^{2}+d^{2}}}}{e}-\frac {d \left (-\frac {1}{5 d e \left (x +\frac {d}{e}\right ) \left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {3}{2}}}+\frac {4 e \left (-\frac {-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e}{6 d^{2} e^{2} \left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {3}{2}}}-\frac {-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e}{3 e^{2} d^{4} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{5 d}\right )}{e^{2}}\) | \(212\) |
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Leaf count of result is larger than twice the leaf count of optimal. 171 vs. \(2 (73) = 146\).
Time = 0.31 (sec) , antiderivative size = 171, normalized size of antiderivative = 2.01 \[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\frac {3 \, e^{5} x^{5} + 3 \, d e^{4} x^{4} - 6 \, d^{2} e^{3} x^{3} - 6 \, d^{3} e^{2} x^{2} + 3 \, d^{4} e x + 3 \, d^{5} - {\left (2 \, e^{4} x^{4} + 2 \, d e^{3} x^{3} - 3 \, d^{2} e^{2} x^{2} - 3 \, d^{3} e x - 3 \, d^{4}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{15 \, {\left (d^{4} e^{7} x^{5} + d^{5} e^{6} x^{4} - 2 \, d^{6} e^{5} x^{3} - 2 \, d^{7} e^{4} x^{2} + d^{8} e^{3} x + d^{9} e^{2}\right )}} \]
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\[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\int \frac {x}{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {5}{2}} \left (d + e x\right )}\, dx \]
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none
Time = 0.20 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.06 \[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\frac {1}{5 \, {\left ({\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e^{3} x + {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d e^{2}\right )}} + \frac {x}{15 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{2} e} + \frac {2 \, x}{15 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{4} e} \]
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\[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\int { \frac {x}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} {\left (e x + d\right )}} \,d x } \]
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Time = 11.79 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.92 \[ \int \frac {x}{(d+e x) \left (d^2-e^2 x^2\right )^{5/2}} \, dx=\frac {\sqrt {d^2-e^2\,x^2}\,\left (3\,d^4+3\,d^3\,e\,x+3\,d^2\,e^2\,x^2-2\,d\,e^3\,x^3-2\,e^4\,x^4\right )}{15\,d^4\,e^2\,{\left (d+e\,x\right )}^3\,{\left (d-e\,x\right )}^2} \]
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